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[JSP/Javajacob-1.17-M2

Description: jacob插件,这个东西说实话我不会用 来上传就是为了能下载东西(Jacob plug-in, this thing, to tell you the truth, I won't upload it just to be able to download things)
Platform: | Size: 465920 | Author: chenshuai | Hits:

[JSP/Javaarray

Description: 小易有一个长度为N的正整数数列A = {A[1], A[2], A[3]..., A[N]}。 牛博士给小易出了一个难题: 对数列A进行重新排列,使数列A满足所有的A[i] * A[i + 1](1 ≤ i ≤ N - 1)都是4的倍数。 小易现在需要判断一个数列是否可以重排之后满足牛博士的要求。 输入描述: 输入的第一行为数列的个数t(1 ≤ t ≤ 10), 接下来每两行描述一个数列A,第一行为数列长度n(1 ≤ n ≤ 10^5) 第二行为n个正整数A[i](1 ≤ A[i] ≤ 10^9) 输出描述: 对于每个数列输出一行表示是否可以满足牛博士要求,如果可以输出Yes,否则输出No。 输入例子1: 2 3 1 10 100 4 1 2 3 4 输出例子1: Yes No */(It has a length of N integers A = {A[1], A[2], A[3], A[N]}... Dr out of a problem for small: The series A rearrange the sequence of A meet all A[i] * A[i + 1] (I = 1 ~ N - 1) are multiples of 4. Xiao Yi now need to determine whether a series can meet the requirements after the rearrangement of Dr. Input description: The number of the first series of T input (t = 1 ~ 10), Then every two lines describe a series of A, the first act of sequence length n (1 N 10^5) Second n positive integer A[i] (1 A[i] 10^9) Output description: For each sequence, output a line indicating whether it can meet the requirements of Dr. Niu, and if you can output Yes, otherwise output No. Input example 1: Two Three 110100 Four 1234 Output example 1: Yes No * /)
Platform: | Size: 688128 | Author: 堪准节 | Hits:

[Other364JSP家政服务系统

Description: 还有很多没做请大佬帮忙,找代码参考参考,希望有帮助(I don't ask for big brother help Find code reference)
Platform: | Size: 13092864 | Author: 青衫水墨 | Hits:

[JSP/Javasousou

Description: JAVA 学士后单元项目 不要问我是谁,我来自郑州! 嗖嗖移动业务大厅代码 嗖嗖移动大厅完整版代码(JAVA bachelor post unit project Don't ask who I am, I'm from Zhengzhou! As the mobile business hall code The hall was full of mobile version of the code.)
Platform: | Size: 14336 | Author: BAT-MA | Hits:

[OtherBatt

Description: java飞行棋源代码,欢迎大家前来下载,非喜勿喷(Java flight chess source code, welcome to download, not happy don't spray)
Platform: | Size: 24139776 | Author: 0814在路上 | Hits:

[Other73462713Router

Description: 实现关于路由器的简单功能。 实现距离矢量路由算法。 所实现的路由器模拟Internet上的IP路由器。它能确定网络的最短路由,并在这些利用上传输分组 实现功能简介 1) 编写一个称为“Router”的程序 2) 利用距离向量算法更新路由表 3) 该程序的多个实例(进程或线程)可以以运行在一台机器 4) 实例之间利用UDP交换路由表 5) 假设结点与其邻居结点的都为距离为1。 6) 为了指明实例及其邻居,程序启动时必须能接收以下参数: 7) router ID, myport, port1, port2, port3… 8) 程序必须能处理以下命令: a) N-打印活动的邻居列表。 b) T-输出路由表。 c) 0,1,… 9-发送分组 9) 关于时间定时 a) 每个路由器每2秒钟发出它们的路由表 b) 每个路由器根据收到的路由表更新它们自己的路由表(This is a parody routing algorithm java program. Achieve a simple function on the router. Implement distance vector routing algorithm. Internet router)
Platform: | Size: 73728 | Author: 韩大侠 | Hits:

[JSP/JavaNovo(a) WinRAR archive

Description: ignore this too, don't waste your time ye
Platform: | Size: 1883136 | Author: asfsdfasdf | Hits:

[JSP/Java2017hw5 (1).pdf

Description: ai file homework for t
Platform: | Size: 76800 | Author: atechtush | Hits:

[Other经典案例

Description: 可增强对se的深入理解和应用 学习不同的语句表达方式(t can enhance the deep understanding and application of Se and learn different sentence expressions)
Platform: | Size: 2850816 | Author: Baney | Hits:

[JSP/Javaminesweeper

Description: Then you can input the command, which includes 3 types: x,y,B Mark the coordinate position (x,y) as a mine, which will be displayed in '@'.It can be cancelled by the input of x,y,N . Everytime you mark a mine, the total number of mines will be subtracted by 1. x,y,N Mark the coordinate position (x,y) as a non-mine location in order to obtain a new tip.The number displayed in the vertex represents the number of neighboring mines adjacent to that square (1 - 8). Notice that if the number is 0, all non-mine locations can be recursively opened around the previous one. The object of the game is to uncover all squares that don't contain mines and mark all the mines.If you uncover a mine, you lose.(Minesweeper, installed by default on most computers that come with Windows, is one of the most classic computer games of all time. Now we can enjoy a much simpler version of the game in the DOS command window)
Platform: | Size: 5120 | Author: jlg098 | Hits:

[Other阿里巴巴Java开发手册(终极版).pdf

Description: 阿里巴巴java开发手册,参考学习规范写程序习惯(t he document about Alibaba)
Platform: | Size: 931840 | Author: Mr.feng.c.z | Hits:

[Other666

Description: 这是用JAVA编的程序,我是初学者,请多指教。(I can't speak English,I don't know.)
Platform: | Size: 327680 | Author: 勇敢的柠檬 | Hits:

[JSP/Java抽奖程序

Description: 输入四位数字,如果中奖输出恭喜中奖了!没中奖则输出很遗憾(Enter four Numbers, and if you win the award, congratulations! I'm sorry I didn't win the prize.)
Platform: | Size: 27648 | Author: 吃鸡的狐狸 | Hits:

[JSP/JavaBukkitForge-master

Description: BukkitForge - a Minecraft mod that ports the Bukkit plugin API to minecraft. This is very WIP. Since i started doing this, i was mostly aiming for a server that didn't crash. It can load plugins, commands work, lots of things work, permissions should work, etc.
Platform: | Size: 25496576 | Author: QuingScriptor | Hits:

[Game Program5javaprogram

Description: 1.游戏要有图形用户界面,界面能够反映游戏所有的细节。 2.界面中要有坦克,墙,树林,河流。 3.界面中要有一个“家”,“家”被攻击中则输了游戏。 4.坦克分两种,敌方和我方。 5.墙也分为两种,可以穿透的普通墙,不可以穿透的铁墙。 6.树和河流均只有一种,树林坦克可以通过。 7.坦克可以发射子弹,敌我方的子弹属性一样。 8.我方子弹可以杀死敌方坦克,敌方子弹也可以杀死我方坦克,但需要多枪子弹才可以杀死。 9.敌方之间不可以杀死对方。(Implement a java version of the tank war game [functional hints] 1. games have a graphical user interface, and the interface can reflect all the details of the game. There are tanks, walls, woods, and rivers in the 2. interface. There is a "home" in the 3. interface, and the "home" is attacked by the game. 4. tanks are divided into two types, the enemy and us. The 5. walls are also divided into two kinds, the ordinary walls that can penetrate, the iron walls that can not be penetrated. There is only one of the 6. trees and rivers, and the forest tanks can pass. 7. tanks can launch bullets, the enemy and our side of the same bullet properties. 8. our bullets can kill the enemy tanks, and the enemy bullets can kill our tanks, but they need multiple guns to kill them. 9. enemies can't kill each other.)
Platform: | Size: 129024 | Author: 阿桑上市分合 | Hits:

[JSP/JavaFileUpload.Java

Description: 文件上传,图片上传(后缀名验证,文件类型验证),大文件分片上传,“秒传”,断点续传,传输失败自动重试,手动重试(f i l e u p l o a d.p i c t u r e u p l o a d.)
Platform: | Size: 344064 | Author: 89ohohi | Hits:

[JSP/JavaCMPP2.0 JAVA代码+模拟器

Description: 1). 拿到接口参数,也就是第一点(有点废话的感觉),默认给你10条短信的机会进行测试。 2). 需要绑定好发送IP,否则提示发送成功,但接不到短信 3). 需要加上签名,测试短信格式如:测试信息2,退订回N【京东商城】(代码里面有 test.java中) 4). 本人测试CMPP的速度不是很快,有好几秒甚至几十秒的等待时间(今天进行的测试-2016-09-01) 如果还无法发送,直接找接口方.....(1). Get the interface parameters, that is, the first point (a little bit of nonsense), the default to you 10 messages of the opportunity to test. 2). It needs to be bound to send IP, otherwise the prompt will be sent, but the message is not received. 3). Need to add the signature, test the message format, such as: Test Information 2, back to the N [Jingdong mall] (in the code test.java) 4). I test the CMPP speed not very quickly, there are several seconds or even dozens of seconds of waiting time (today's test -2016-09-01) If you can't send it, look for the interface directly...)
Platform: | Size: 951296 | Author: kelvin178 | Hits:

[e-language冒泡算法排序

Description: 功能说明?什么功能?说明什么?什么啊?根本看不懂。。(Function description? What is the function? What does it mean?What ah? I don't understand it at all.)
Platform: | Size: 1024 | Author: 麦凯乐 | Hits:

[JSP/Javaxcb-with-driver

Description: There are many variations of passages of Lorem Ipsum available, but the majority have suffered alteration in some form, by injected humour, or randomised words which don't look even slightly believable. If you are going to use a passage of Lorem Ipsum, you need to be sure there isn't anything embarrassing hidden in the middle of text
Platform: | Size: 794624 | Author: ronantav | Hits:

[JSP/Java嗖嗖移动业务大厅

Description: java学习 嗖嗖便民信息平台。。。。。。(I won't be able to write in order to download resources to register.............)
Platform: | Size: 1216512 | Author: 阿苗喵喵喵 | Hits:
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